Diatomic distance on each EXAFS of both elements

Dear Quiang, basically you are asking whether the distance A-B is equal to the distance B-A. I would say, obviously this should be the case. If you measured both edges and you fit both spectra together you can (and will most probably) use this trivial fact to reduce the number of free parameters. But, maybe that was not your question. You rightly mention the phase shift. It will be different, however the difference should be small. The phase shift has a Z dependency, but since Cu and Zn are neighbours in the PSE the difference is small. So if you look (very) closely on the not phase shift corrected FT you will see a small difference between the respective peaks in the two FT. You might have a look here: https://urldefense.us/v3/__https://speakerdeck.com/bruceravel/exafs-phase-sh... Best regards, Edmund On 27.02.25 09:25, "Qiang Chang (常强)" via Ifeffit wrote:

Hi Qiang,
The fitted distance, as seen from each of the metal atoms should be the same, however, the Real Space Fourier Transform of the two edges may not have the peak in the same position because of the phase shift which will differ in the two paths. The phase shift depends on the backscatterer and that is clearly different depending on the absorber atom.
Carlo
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Carlo Segre, Duchossois Professor of Physics
Illinois Institute of Technology
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From: "Qiang Chang (常强)" via Ifeffit
participants (3)
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"Qiang Chang (常强)"
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Carlo Segre
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Edmund Welter