Au-foil (fcc) splitted peak
Julian - the scattering amplitudes of all elements have structure in them that are connected to electron scattering (Ramsauer-Townsend) resonances within the backscattering atom. For light elements (e.g. O, S, Fe) they occur at energies that are lower than the typical transform range, so they usually are ignored. For heavier scatterers like Au there are strong minima and maxima in the Au scattering amplitude over the transform range. From a signal processing point of view, these amplitude modulations look like beats, which normally are due to different distances interfering. In the case of Au back scatterers, even if there is only one physical distance, you will get multiple peaks (perhaps overlapping). Mathematically the fourier transform is the distance distribution convoluted with the fourier transform of the amplitude. So, how do you deal with it? First, if you know what's going on that may be enough. Alternatively, if all the scatterers are the same, it's not difficult to divide out the scattering amplitude and subtract out the scattering phase before the transform to obtain an "optical transform", which eliminates the effect you're seeing. I don't know if that is supported by ifeffit but it's not hard to do. This approach is less useful if you have multiple types of scatterers (e.g. Au, S) because if you do the compensation for one type of scatterer it screws it up for the others. Techniques like regularization are probably better in that case. hope that helps grant bunker
Dear Wayne and Grant Bunker, thanks a lot for the explanation! To be honest, I didn't know the Ramsauer-Townsend effect before. I think it's ok to show the spektra without subtracting out the scattering phase. As long as I know what's going on and as long as I can explain it it will be fine. Thanks so much for your help! Julian ________________________________________ Von: ifeffit-bounces@millenia.cars.aps.anl.gov [ifeffit-bounces@millenia.cars.aps.anl.gov]" im Auftrag von "grant bunker [bunker@iit.edu] Gesendet: Sonntag, 9. Oktober 2011 21:38 Bis: ifeffit@millenia.cars.aps.anl.gov Betreff: [Ifeffit] Au-foil (fcc) splitted peak Julian - the scattering amplitudes of all elements have structure in them that are connected to electron scattering (Ramsauer-Townsend) resonances within the backscattering atom. For light elements (e.g. O, S, Fe) they occur at energies that are lower than the typical transform range, so they usually are ignored. For heavier scatterers like Au there are strong minima and maxima in the Au scattering amplitude over the transform range. From a signal processing point of view, these amplitude modulations look like beats, which normally are due to different distances interfering. In the case of Au back scatterers, even if there is only one physical distance, you will get multiple peaks (perhaps overlapping). Mathematically the fourier transform is the distance distribution convoluted with the fourier transform of the amplitude. So, how do you deal with it? First, if you know what's going on that may be enough. Alternatively, if all the scatterers are the same, it's not difficult to divide out the scattering amplitude and subtract out the scattering phase before the transform to obtain an "optical transform", which eliminates the effect you're seeing. I don't know if that is supported by ifeffit but it's not hard to do. This approach is less useful if you have multiple types of scatterers (e.g. Au, S) because if you do the compensation for one type of scatterer it screws it up for the others. Techniques like regularization are probably better in that case. hope that helps grant bunker _______________________________________________ Ifeffit mailing list Ifeffit@millenia.cars.aps.anl.gov http://millenia.cars.aps.anl.gov/mailman/listinfo/ifeffit ________________________________ Helmholtz-Zentrum Berlin für Materialien und Energie GmbH Mitglied der Hermann von Helmholtz-Gemeinschaft Deutscher Forschungszentren e.V. Aufsichtsrat: Vorsitzender Prof. Dr. Dr. h.c. mult. Joachim Treusch, stv. Vorsitzende Dr. Beatrix Vierkorn-Rudolph Geschäftsführer: Prof. Dr. Anke Rita Kaysser-Pyzalla, Dr. Ulrich Breuer Sitz Berlin, AG Charlottenburg, 89 HRB 5583 Postadresse: Hahn-Meitner-Platz 1 D-14109 Berlin http://www.helmholtz-berlin.de
2011/10/11, Kaiser, Julian
Dear Wayne and Grant Bunker,
thanks a lot for the explanation! To be honest, I didn't know the Ramsauer-Townsend effect before. I think it's ok to show the spektra without subtracting out the scattering phase. As long as I know what's going on and as long as I can explain it it will be fine.
Thanks so much for your help! Julian
________________________________________ Von: ifeffit-bounces@millenia.cars.aps.anl.gov [ifeffit-bounces@millenia.cars.aps.anl.gov]" im Auftrag von "grant bunker [bunker@iit.edu] Gesendet: Sonntag, 9. Oktober 2011 21:38 Bis: ifeffit@millenia.cars.aps.anl.gov Betreff: [Ifeffit] Au-foil (fcc) splitted peak
Julian - the scattering amplitudes of all elements have structure in them that are connected to electron scattering (Ramsauer-Townsend) resonances within the backscattering atom. For light elements (e.g. O, S, Fe) they occur at energies that are lower than the typical transform range, so they usually are ignored. For heavier scatterers like Au there are strong minima and maxima in the Au scattering amplitude over the transform range. From a signal processing point of view, these amplitude modulations look like beats, which normally are due to different distances interfering. In the case of Au back scatterers, even if there is only one physical distance, you will get multiple peaks (perhaps overlapping). Mathematically the fourier transform is the distance distribution convoluted with the fourier transform of the amplitude.
So, how do you deal with it? First, if you know what's going on that may be enough. Alternatively, if all the scatterers are the same, it's not difficult to divide out the scattering amplitude and subtract out the scattering phase before the transform to obtain an "optical transform", which eliminates the effect you're seeing. I don't know if that is supported by ifeffit but it's not hard to do. This approach is less useful if you have multiple types of scatterers (e.g. Au, S) because if you do the compensation for one type of scatterer it screws it up for the others. Techniques like regularization are probably better in that case.
hope that helps
grant bunker
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Aufsichtsrat: Vorsitzender Prof. Dr. Dr. h.c. mult. Joachim Treusch, stv. Vorsitzende Dr. Beatrix Vierkorn-Rudolph Geschäftsführer: Prof. Dr. Anke Rita Kaysser-Pyzalla, Dr. Ulrich Breuer
Sitz Berlin, AG Charlottenburg, 89 HRB 5583
Postadresse: Hahn-Meitner-Platz 1 D-14109 Berlin
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