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k

Hello,

The XAFS "photoelectron wave number" k is always determined from the TOTAL
photoelectron energy: k^2=\hbar\omega-E_c. Whereas the real (deBroglie) wave
is determined from the KINETIC energy: k^2=T.
These two k's are not the same since the potential is essentially non-zero
in the vicinity of atomic cores (otherwise we wouldn't have XAFS phase
shifts).

Q1: What is the physical meaning of the XAFS k? Is it just a convenient
something for subsequent Fourier analysis?
Q2: This artificial "k" (or "p") is included somehow into FEFF calculations.
Does this  imitation of real k affect the calculations? In which step
mostly? Extrinsic losses are incorporated into FEFF - as k- or E- dependent?

Thanks in advance for your answers,

Konstantin
__________________________________
Dr. K. Klementiev
HASYLAB/DESY
Notkestrasse 85,
D-22607 Hamburg
Tel.: (+49)-40-8998-2932
E-mail: Konstantin.Klementiev@desy.de