Hello, all. It is a low- to medium- level brain teaser. Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why? Anatoly [image: image.png]
Hi Anatoly, reflectivity of Pt over that energy range does not vary that much: [image: image.png] I guessed what angle you were set for, assuming Pd K-edge... So something wrong with I0? -R. On Wed, Jun 14, 2023 at 5:28 PM Anatoly Frenkel < anatoly.frenkel@stonybrook.edu> wrote:
Hello, all. It is a low- to medium- level brain teaser.
Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why?
Anatoly
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One thing that's pretty odd is that the glitches are peaks in I0, and dips in It. It would be much easier to explain if It was the one that increased steeply and I0 was more linear, but the presence of the edge in It shows that you didn't switch them. Red = It. What's that sudden drop at the end? Could it be that the I0 chamber is misaligned so that beam is scraping one of the plates? That could cause all sorts of odd things to happen. mam On 6/14/2023 5:27 PM, Anatoly Frenkel wrote:
Hello, all. It is a low- to medium- level brain teaser.
Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why?
Anatoly
image.png
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Thank you, Matthew and Robert, but I think the explanation is more simplle. The fact that there are peaks in I0 and dips in transmission is a clue that explains why transmission is almost linear while I0 curves up. Anatoly
On Jun 14, 2023, at 11:34 PM, matthew marcus
wrote: One thing that's pretty odd is that the glitches are peaks in I0, and dips in It. It would be much easier to explain if It was the one that increased steeply and I0 was more linear, but the presence of the edge in It shows that you didn't switch them. Red = It. What's that sudden drop at the end?
Could it be that the I0 chamber is misaligned so that beam is scraping one of the plates? That could cause all sorts of odd things to happen. mam
On 6/14/2023 5:27 PM, Anatoly Frenkel wrote: Hello, all. It is a low- to medium- level brain teaser. Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why? Anatoly image.png _______________________________________________ Ifeffit mailing list Ifeffit@millenia.cars.aps.anl.gov http://millenia.cars.aps.anl.gov/mailman/listinfo/ifeffit Unsubscribe: http://millenia.cars.aps.anl.gov/mailman/options/ifeffit
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Suppose the mono is being used at the 333 reflection (for Si), intentionally working at the 3rd harmonic. In that case, if the fundamental isn't filtered out, you could get just what we see, with the sample doing the filtering before the beam gets to the transmission chamber. mam On 6/14/2023 9:16 PM, Anatoly Frenkel wrote:
Thank you, Matthew and Robert, but I think the explanation is more simplle. The fact that there are peaks in I0 and dips in transmission is a clue that explains why transmission is almost linear while I0 curves up.
Anatoly
On Jun 14, 2023, at 11:34 PM, matthew marcus
wrote: One thing that's pretty odd is that the glitches are peaks in I0, and dips in It. It would be much easier to explain if It was the one that increased steeply and I0 was more linear, but the presence of the edge in It shows that you didn't switch them. Red = It. What's that sudden drop at the end?
Could it be that the I0 chamber is misaligned so that beam is scraping one of the plates? That could cause all sorts of odd things to happen. mam
On 6/14/2023 5:27 PM, Anatoly Frenkel wrote: Hello, all. It is a low- to medium- level brain teaser. Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why? Anatoly image.png _______________________________________________ Ifeffit mailing list Ifeffit@millenia.cars.aps.anl.gov http://millenia.cars.aps.anl.gov/mailman/listinfo/ifeffit Unsubscribe: http://millenia.cars.aps.anl.gov/mailman/options/ifeffit
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Amazing idea. I thunk you were the only one who succeeded to use third harmonic of Si for taking EXAFS at high atomic number elements. But that does not explain the peaks and dips. Anatoly
On Jun 15, 2023, at 12:22 AM, matthew marcus
wrote: Suppose the mono is being used at the 333 reflection (for Si), intentionally working at the 3rd harmonic. In that case, if the fundamental isn't filtered out, you could get just what we see, with the sample doing the filtering before the beam gets to the transmission chamber. mam
On 6/14/2023 9:16 PM, Anatoly Frenkel wrote: Thank you, Matthew and Robert, but I think the explanation is more simplle. The fact that there are peaks in I0 and dips in transmission is a clue that explains why transmission is almost linear while I0 curves up. Anatoly
On Jun 14, 2023, at 11:34 PM, matthew marcus
wrote: One thing that's pretty odd is that the glitches are peaks in I0, and dips in It. It would be much easier to explain if It was the one that increased steeply and I0 was more linear, but the presence of the edge in It shows that you didn't switch them. Red = It. What's that sudden drop at the end?
Could it be that the I0 chamber is misaligned so that beam is scraping one of the plates? That could cause all sorts of odd things to happen. mam
On 6/14/2023 5:27 PM, Anatoly Frenkel wrote: Hello, all. It is a low- to medium- level brain teaser. Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why? Anatoly image.png _______________________________________________ Ifeffit mailing list Ifeffit@millenia.cars.aps.anl.gov http://millenia.cars.aps.anl.gov/mailman/listinfo/ifeffit Unsubscribe: http://millenia.cars.aps.anl.gov/mailman/options/ifeffit
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Well, I’ll take a shot. Looks like the mirror angle is totally fubared, you are getting Bragg peaks from the coating or substrate that are giving you the peaks in Io. Since you have no idea what angle those are going through Io, they are unlikely to make it into either the sample or It. Since those photons are removed from the beam hitting the sample, they would show up as intensity dips in It. I’d bet that most (all?) of the reflected beam is not going into the sample. I’m kind of surprised It signal is as clean as it is, but then I don’t know the gains on either measurement amplifiers. I couldn’t find a flat mirror angle that would cause the cutoff at 12870? eV but since it is a collimating mirror who knows what range of angles were actually being hit. Jeff Terry Interim Chair, Department of Biology Interim Chair, Department of Social Sciences Professor of Physics Professor of Mechanical, Materials, and Aerospace Engineering Editor, Applied Surface Science Illinois Institute of Technology 3101 S. Dearborn St. Chicago IL 60616 630-252-9708
On Jun 14, 2023, at 7:27 PM, Anatoly Frenkel
wrote: Hello, all. It is a low- to medium- level brain teaser.
Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why?
Anatoly
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The mirror was set up for a run at the Pd K-edge, according to the problem statement. Therefore, its nominal angle must be such as to put the critical energy >25keV. An angle of 3mrad would do it. At that angle, the reflectivity (assuming no roughness) goes up with energy in the relevant range, but only by a few percent. We're not told what the ratio of gains of the current amps is, or whether the ion chambers have the same path length, so we can't tell whether the signals are comparable, as shown on the graph, or orders of magnitude different. mam On 6/14/2023 10:17 PM, Jeffrey Terry wrote:
Well, I’ll take a shot. Looks like the mirror angle is totally fubared, you are getting Bragg peaks from the coating or substrate that are giving you the peaks in Io. Since you have no idea what angle those are going through Io, they are unlikely to make it into either the sample or It. Since those photons are removed from the beam hitting the sample, they would show up as intensity dips in It. I’d bet that most (all?) of the reflected beam is not going into the sample. I’m kind of surprised It signal is as clean as it is, but then I don’t know the gains on either measurement amplifiers. I couldn’t find a flat mirror angle that would cause the cutoff at 12870? eV but since it is a collimating mirror who knows what range of angles were actually being hit.
Jeff Terry Interim Chair, Department of Biology Interim Chair, Department of Social Sciences Professor of Physics Professor of Mechanical, Materials, and Aerospace Engineering Editor, Applied Surface Science Illinois Institute of Technology 3101 S. Dearborn St. Chicago IL 60616 630-252-9708
On Jun 14, 2023, at 7:27 PM, Anatoly Frenkel
mailto:anatoly.frenkel@stonybrook.edu> wrote: Hello, all. It is a low- to medium- level brain teaser.
Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why?
Anatoly
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I'm not sure why the intensity would go up unless the ion chamber was poorly set up. But, as others have pointed out, the mirror reflectivity for a Pt mirror should not change significantly over this energy range - the energy range is not that close to the Pt L3 or L2 edges. Depending on where it was located, fluorescence from the Pt mirror might pollute the signal in the I0 ion chamber, but that would also likely be a fairly constant background. But, why would you fill the I0 ion chamber with Argon? A 10-cm ion chamber filled with Ar would absorb about 50% of the beam at 12 keV. Even at 24 keV, that would absorb 8% of the beam - not necessarily a problem but also probably generating at least a micro-Amp, so way more signal than you would need. For mirror reflectivity curves, allow me to humbly remind everyone of https://xraydb.xrayabsorption.org/reflectivity/Pt/21.45/2.5/10/s/1000/51000/... which is both interactive and works with X-ray energies above 30 keV. On Wed, Jun 14, 2023 at 7:28 PM Anatoly Frenkel < anatoly.frenkel@stonybrook.edu> wrote:
Hello, all. It is a low- to medium- level brain teaser.
Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why?
Anatoly
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-- --Matt Newville <newville at cars.uchicago.edu> 630-327-7411
I would have guessed that the increase in I0 is primarily due to Pt
fluorescence. The yield does increase as the energy rises.
Carlo
On Thu, Jun 15, 2023 at 9:45 AM Matt Newville
I'm not sure why the intensity would go up unless the ion chamber was poorly set up. But, as others have pointed out, the mirror reflectivity for a Pt mirror should not change significantly over this energy range - the energy range is not that close to the Pt L3 or L2 edges. Depending on where it was located, fluorescence from the Pt mirror might pollute the signal in the I0 ion chamber, but that would also likely be a fairly constant background.
But, why would you fill the I0 ion chamber with Argon? A 10-cm ion chamber filled with Ar would absorb about 50% of the beam at 12 keV. Even at 24 keV, that would absorb 8% of the beam - not necessarily a problem but also probably generating at least a micro-Amp, so way more signal than you would need.
For mirror reflectivity curves, allow me to humbly remind everyone of
https://xraydb.xrayabsorption.org/reflectivity/Pt/21.45/2.5/10/s/1000/51000/...
which is both interactive and works with X-ray energies above 30 keV.
On Wed, Jun 14, 2023 at 7:28 PM Anatoly Frenkel < anatoly.frenkel@stonybrook.edu> wrote:
Hello, all. It is a low- to medium- level brain teaser.
Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why?
Anatoly
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-- Carlo U. Segre (he/him) -- Duchossois Leadership Professor of Physics Professor of Materials Science & Engineering Director, Center for Synchrotron Radiation Research and Instrumentation Illinois Institute of Technology Voice: 312.567.3498 Fax: 312.567.3494 segre@iit.edu http://phys.iit.edu/~segre segre@debian.org
Hi Anatoly, I think Robert or Matthew made this point, but if set up for Pd, the mirror angle may have been chosen to reject ~70 keV, but possibly not 36 keV -- the harmonic at the Au edge. Do you know what the mirror angle was? The Ar-filled I0 would be very efficient at absorbing 12 keV, and only pretty efficient at absorbing 36 keV. That would leave a more harmonic-rich beam exiting I0 and hitting the sample than entering I0. The good news is that the dense Pd/Au sample would be efficient at absorbing 36 keV too (but it was ~1 absorption length at 24 keV?) too. Mono reflectivity of 36 keV vs 12 keV might also factor in. If you were not deliberately detuning but the crystals were slightly misaligned, the harmonic content may change significantly over the scan range. I would not guess that to dominate, but maybe it factors in. On Thu, Jun 15, 2023 at 9:54 AM Anatoly Frenkel < anatoly.frenkel@stonybrook.edu> wrote:
Thank you, Matt. Ion chambers were filled with 90% Ar, and Pt coating was used, because we were measuring Pd K edge for the project, but we decided to look at the Au edge for testing purposes.
Anatoly
On Jun 15, 2023, at 10:45 AM, Matt Newville
wrote: I'm not sure why the intensity would go up unless the ion chamber was poorly set up. But, as others have pointed out, the mirror reflectivity for a Pt mirror should not change significantly over this energy range - the energy range is not that close to the Pt L3 or L2 edges. Depending on where it was located, fluorescence from the Pt mirror might pollute the signal in the I0 ion chamber, but that would also likely be a fairly constant background.
But, why would you fill the I0 ion chamber with Argon? A 10-cm ion chamber filled with Ar would absorb about 50% of the beam at 12 keV. Even at 24 keV, that would absorb 8% of the beam - not necessarily a problem but also probably generating at least a micro-Amp, so way more signal than you would need.
For mirror reflectivity curves, allow me to humbly remind everyone of
https://xraydb.xrayabsorption.org/reflectivity/Pt/21.45/2.5/10/s/1000/51000/...
which is both interactive and works with X-ray energies above 30 keV.
On Wed, Jun 14, 2023 at 7:28 PM Anatoly Frenkel < anatoly.frenkel@stonybrook.edu> wrote:
Hello, all. It is a low- to medium- level brain teaser.
Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why?
Anatoly
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-- --Matt Newville <newville at cars.uchicago.edu> 630-327-7411
HI Mike, it is dilute Pd in Au nanoparticles deposited on SiO2 with about
5% metal weight loading.
In my view, the lack of curvature in transmission (the original problem in
my post) is a simple consequence of two opposite trends, 1) the curving up
of the transmission signal by the same reason (yet to be identified, which
is something I will try to, after getting useful hints from many people
here) as the curving up of the incident beam and 2) the opposite trend due
to the greater removal of the photons at higher energy by I0 detector. The
two opposite trends tend to cancel each other.
Anatoly
On Thu, Jun 15, 2023 at 4:14 PM Mike Massey
A question because I'm not really super clear on how harmonics work:
(I'll get to the question in a moment...) I note that I0 starts to go non-linear around 12200-12400 eV and stays that way. So an increase (proportional?) in the amount of signal in It might be happening at around the same point.
Could Pd fluorescence into It be impacting the signal in It? I realize that the Pd emission lines are very low in energy but they are around 3k eV.
I'm not super familiar with alloy systems but I did have an issue once upon a time with back fluorescence into an ion chamber and things went a bit wonky. This wouldn't exactly be "back" fluorescence, but if the system is mostly Pd with a little bit of Au, I guess...? And it might be easy enough to test, just put a high-pass filter in front of It?
I got nothin' but it's kinda fun to take a shot. Cheers,
Mike
On Jun 16, 2023, at 03:26, Matt Newville
wrote: Hi Anatoly,
I think Robert or Matthew made this point, but if set up for Pd, the mirror angle may have been chosen to reject ~70 keV, but possibly not 36 keV -- the harmonic at the Au edge. Do you know what the mirror angle was?
The Ar-filled I0 would be very efficient at absorbing 12 keV, and only pretty efficient at absorbing 36 keV. That would leave a more harmonic-rich beam exiting I0 and hitting the sample than entering I0. The good news is that the dense Pd/Au sample would be efficient at absorbing 36 keV too (but it was ~1 absorption length at 24 keV?) too.
Mono reflectivity of 36 keV vs 12 keV might also factor in. If you were not deliberately detuning but the crystals were slightly misaligned, the harmonic content may change significantly over the scan range. I would not guess that to dominate, but maybe it factors in.
On Thu, Jun 15, 2023 at 9:54 AM Anatoly Frenkel < anatoly.frenkel@stonybrook.edu> wrote:
Thank you, Matt. Ion chambers were filled with 90% Ar, and Pt coating was used, because we were measuring Pd K edge for the project, but we decided to look at the Au edge for testing purposes.
Anatoly
On Jun 15, 2023, at 10:45 AM, Matt Newville
wrote: I'm not sure why the intensity would go up unless the ion chamber was poorly set up. But, as others have pointed out, the mirror reflectivity for a Pt mirror should not change significantly over this energy range - the energy range is not that close to the Pt L3 or L2 edges. Depending on where it was located, fluorescence from the Pt mirror might pollute the signal in the I0 ion chamber, but that would also likely be a fairly constant background.
But, why would you fill the I0 ion chamber with Argon? A 10-cm ion chamber filled with Ar would absorb about 50% of the beam at 12 keV. Even at 24 keV, that would absorb 8% of the beam - not necessarily a problem but also probably generating at least a micro-Amp, so way more signal than you would need.
For mirror reflectivity curves, allow me to humbly remind everyone of
https://xraydb.xrayabsorption.org/reflectivity/Pt/21.45/2.5/10/s/1000/51000/...
which is both interactive and works with X-ray energies above 30 keV.
On Wed, Jun 14, 2023 at 7:28 PM Anatoly Frenkel < anatoly.frenkel@stonybrook.edu> wrote:
Hello, all. It is a low- to medium- level brain teaser.
Pt-coated collimating mirror was in place for Pd K-edge measurement, but Au L3-edge of Pd-Au alloy was measured (for testing purposes). I0 and It detectors were both Ar filled ionization chambers. Because of the energy dependence of reflectivity of the Pt mirror, I0 intensity was strongly nonlinear (blue curve). However, the transmission intensity in the It detector was almost linear (red curve). Why?
Anatoly
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participants (7)
-
Anatoly Frenkel
-
Carlo Segre
-
Jeffrey Terry
-
Matt Newville
-
matthew marcus
-
Mike Massey
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Robert Gordon