Dear members, I have seen many times the absorption length in materials for introduction of XAFS. The absorption length equals 1/mu, which is the thickness that I0 is attenuated to 1/e. But I do not understand why the absorption length is important. More importantly, I do not understand why the particle size in samples should be smaller than the absorption length. Could any one explain the absorption length including the question above and the relation between the absorption length and edge step calculations? Thanks in advance. Kug-Seung Lee Kug-Seung Lee, Ph.D. Staff Scientist Manager, 8C Nano Probe XAFS Beamline Pohang Accelerator Laboratory Pohang 790-784, Republic of Korea Office: +82-54-279-1522 Fax: +82-54-279-1599 C. P.: +82-10-6419-7801 Researcher ID: http://www.researcherid.com/rid/D-7088-2011
Rob Scarrow did a particularly good job with this topic: http://xafs.org/Workshops/NSLS2002?action=AttachFile&do=view&target=Scarrow.pdf
—Scott
On Mar 9, 2016, at 7:54 PM, 이국승(에너지환경소재연구팀)
?Hi Scott,
Thank you for the great presentation material.
It helps me a lot.
Kug-Seung Lee
Kug-Seung Lee, Ph.D.
Staff Scientist
Manager, 8C Nano Probe XAFS Beamline
Pohang Accelerator Laboratory
Pohang 790-784, Republic of Korea
Office: +82-54-279-1522
Fax: +82-54-279-1599
C. P.: +82-10-6419-7801
Researcher ID: http://www.researcherid.com/rid/D-7088-2011
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보낸 사람: Ifeffit
participants (2)
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Scott Calvin -
이국승(에너지환경소재연구팀)