[Ifeffit] N-idp

Hi All Greetings. I have a generic question. Does the Number of independent points in the data set depend on the step size (in k or E) of the scan during data collection? As I see Nidp = (2/pi)*(deltak * deltaR), there is no reference to the scan step. In a scan of small step size, I would expect a lot more data points than a scan with larger step size. But, as per the formula I am left with the same number of idp's irrespective of the scan step. Am I missing something? Regards Shan Shantanu Behera http://www.lehigh.edu/~skb204