Hi JeongEunSuk,
It is known that So2 is the relaxing factor of passive electron. So I think that So2 is affected by neighboring atoms because the potential is made by those Especially, If neighboring atoms are heavy atoms, the contribution will increase. Is it right? If it is right, what is the dependence of So2 on neighbor atoms?
Usually S02 is separated from other loss terms as the "passive electron" factor, to account for the relaxation of the other Z-1 electrons to the sudden presence of that 1 core hole that the absorption process created. In this view, it is purely an effect of the absorbing atom, and is not affected by the neighboring atoms. In a quantum mechanical view of Fermi's Golden rule, absorption is a transition of an atom from an initial (ground) state of an atom to a final (excited) state of the atom. Most of the change is the presence of that core hole (which gives the edge jump), a lesser part of the change comes from the created photo-electron interfering with the neighbor atoms (which gives the EXAFS), and a smaller part yet comes from the Z-1 electrons of the atom relaxing to the presence of the core hole (which gives S02). You are right that the highest energy-level electrons of atom (ie, those least bound to the atom), will interact with neighboring atoms, and therefore change the potential. From the point of view of deep core levels, the chemical bonding of the valence-level electrons is a pretty small perturbation and is generally ignored when considering S02. Of course, for analysis, the S02 parameter is more or less a fudge factor covering up some sins in the measurement and other sins in the approximations in the calculations for the loss terms. --Matt