Hi Irmi: The calculation gives the fraction of the incident photons (in percentage) which are _absorbed_ in the ionization chamber. The length of the chamber, the gas mixture and the incident energy are the parameters you have to put in to the calculation. HTH Carlo On Tue, 17 Apr 2007, I.Reitz wrote:
Dear list members,
can you please tell me, what the ion chamber utility calculates. I did not understand the perl code.
Does it give me first the percentage absorbed via Beers law und then give me the Nbofphotonsabsorbed, that means the flux absorbed in the chamber
or is the result that gives the program out the "number of transmitted photons" after the chamber?
Thank you Irmi
-- Carlo U. Segre -- Professor of Physics Associate Dean for Special Projects, Graduate College Illinois Institute of Technology Voice: 312.567.3498 Fax: 312.567.3494 segre@iit.edu http://www.iit.edu/~segre segre@debian.org