Re: [Ifeffit] Absorption length

?Hi Scott, Thank you for the great presentation material. It helps me a lot. Kug-Seung Lee Kug-Seung Lee, Ph.D. Staff Scientist Manager, 8C Nano Probe XAFS Beamline Pohang Accelerator Laboratory Pohang 790-784, Republic of Korea Office: +82-54-279-1522 Fax: +82-54-279-1599 C. P.: +82-10-6419-7801 Researcher ID: http://www.researcherid.com/rid/D-7088-2011 ________________________________ 보낸 사람: Ifeffit 대신 Scott Calvin 보낸 날짜: 2016년 3월 10일 목요일 오전 10:13 받는 사람: XAFS Analysis using Ifeffit 제목: Re: [Ifeffit] Absorption length Rob Scarrow did a particularly good job with this topic: http://xafs.org/Workshops/NSLS2002?action=AttachFile&do=view&target=Scarrow.pdf -Scott On Mar 9, 2016, at 7:54 PM, 이국승(에너지환경소재연구팀) mailto:lks3006@postech.ac.kr> wrote: Dear members, I have seen many times the absorption length in materials for introduction of XAFS. The absorption length equals 1/mu, which is the thickness that I0 is attenuated to 1/e. But I do not understand why the absorption length is important. More importantly, I do not understand why the particle size in samples should be smaller than the absorption length. Could any one explain the absorption length including the question above and the relation between the absorption length and edge step calculations? Thanks in advance. Kug-Seung Lee Kug-Seung Lee, Ph.D. Staff Scientist Manager, 8C Nano Probe XAFS Beamline Pohang Accelerator Laboratory Pohang 790-784, Republic of Korea Office: +82-54-279-1522 Fax: +82-54-279-1599 C. P.: +82-10-6419-7801 Researcher ID: http://www.researcherid.com/rid/D-7088-2011 _______________________________________________ Ifeffit mailing list Ifeffit@millenia.cars.aps.anl.govmailto:Ifeffit@millenia.cars.aps.anl.gov http://millenia.cars.aps.anl.gov/mailman/listinfo/ifeffit Unsubscribe: http://millenia.cars.aps.anl.gov/mailman/options/ifeffit