[Ifeffit] Absorption length

이국승(에너지환경소재연구팀) lks3006 at postech.ac.kr
Fri Mar 11 05:20:00 CST 2016


?Hi Scott,

Thank you for the great presentation material.

It helps me a lot.


Kug-Seung Lee




Kug-Seung Lee, Ph.D.
Staff Scientist
Manager, 8C Nano Probe XAFS Beamline
Pohang Accelerator Laboratory

Pohang 790-784, Republic of Korea

Office: +82-54-279-1522
Fax: +82-54-279-1599
C. P.: +82-10-6419-7801
Researcher ID: http://www.researcherid.com/rid/D-7088-2011



________________________________
보낸 사람: Ifeffit <ifeffit-bounces at millenia.cars.aps.anl.gov> 대신 Scott Calvin <scalvin at sarahlawrence.edu>
보낸 날짜: 2016년 3월 10일 목요일 오전 10:13
받는 사람: XAFS Analysis using Ifeffit
제목: Re: [Ifeffit] Absorption length

Rob Scarrow did a particularly good job with this topic: http://xafs.org/Workshops/NSLS2002?action=AttachFile&do=view&target=Scarrow.pdf

-Scott

On Mar 9, 2016, at 7:54 PM, 이국승(에너지환경소재연구팀) <lks3006 at postech.ac.kr<mailto:lks3006 at postech.ac.kr>> wrote:

Dear members,
I have seen many times the absorption length in materials for introduction of XAFS.
The absorption length equals 1/mu, which is the thickness that I0 is attenuated to 1/e.
But I do not understand why the absorption length is important.
More importantly, I do not understand why the particle size in samples should be smaller than the absorption length.
Could any one explain the absorption length including the question above and the relation between the absorption length and edge step calculations?
Thanks in advance.

Kug-Seung Lee


Kug-Seung Lee, Ph.D.
Staff Scientist
Manager, 8C Nano Probe XAFS Beamline
Pohang Accelerator Laboratory
Pohang 790-784, Republic of Korea

Office: +82-54-279-1522
Fax: +82-54-279-1599
C. P.: +82-10-6419-7801
Researcher ID: http://www.researcherid.com/rid/D-7088-2011

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