Zhaomo,
I suspect that you have jumped right into EXAFS. You should
really make use of the numerous resources available to get a
better handle on data analysis. You would make far better
progress in EXAFS than waiting around for answers here.
Chris
********************************
Christopher J. Patridge, PhD
NRC Post Doctoral Research Associate
Naval Research Laboratory
Washington, DC 20375
Cell: 315-529-0501
On 1/4/2013 3:48 AM, Zhaomo Tian wrote:
Dear all,
I try to analyze EXAFS data(Cu k-edge was probed) of bare Cu
thin film and Cu thin film with CO gas adsorption. However,
before the fitting, I found that the first main peak of bare Cu
thin film appears at R around 2.2 angstrom, but the nearest
neighbor distance of Cu is actually at R around 2.5 angstrom,
are there something wrong with my data or is it a normal
phenomenon? And when I tried phase correction in Athena or used
FEFF calculated 1st path for phase correction in Artemis, the
peak became closed to R=2.5 angstrom, which seemed more
reasonable. But I guess phase correction is not a necessary
process, then what should I do to make the 1st main peak
position consistent with the right value?
I also attached other 3 data for CO adsorbed Cu(Cu 1do CO, Cu
2do CO and Cu 5do CO. 1do, 2do and 5do mean that the incident
angle of X-ray on sample is 1°, 2° and 5° ), Cu is 300nm
thickness thin film deposited on SiO2/Si, and CO was injected
through the whole measurement and adsorbed on the Cu surface.
Unfortunately, the data for Cu 5do with and without CO are
generally the same, I guess this happened because C-Cu, Cu-O or
C-O paths are too weak to be observed, major Cu-Cu scattering
still dominant even if with CO adsorption, is this right? But Cu
1do CO and Cu 2do CO data are different with bare Cu signal,
especially Cu 1do CO, in FT spectrum, it shows a small peak at R
around 1.1 angstrom and a shoulder at R around 1.9 angstrom, is
it possible for them to stand for C-O and C-Cu path
respectively??(I checked C-O and C-Cu distance for CO adsorbed
Cu in the reference, both are coincident with such values). Now
I have no idea on my situation and come to ask for your he! lp..
Thanks so much!
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